(2x^2+3x-4)(x+4)=0

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Solution for (2x^2+3x-4)(x+4)=0 equation:


Simplifying
(2x2 + 3x + -4)(x + 4) = 0

Reorder the terms:
(-4 + 3x + 2x2)(x + 4) = 0

Reorder the terms:
(-4 + 3x + 2x2)(4 + x) = 0

Multiply (-4 + 3x + 2x2) * (4 + x)
(-4(4 + x) + 3x * (4 + x) + 2x2 * (4 + x)) = 0
((4 * -4 + x * -4) + 3x * (4 + x) + 2x2 * (4 + x)) = 0
((-16 + -4x) + 3x * (4 + x) + 2x2 * (4 + x)) = 0
(-16 + -4x + (4 * 3x + x * 3x) + 2x2 * (4 + x)) = 0
(-16 + -4x + (12x + 3x2) + 2x2 * (4 + x)) = 0
(-16 + -4x + 12x + 3x2 + (4 * 2x2 + x * 2x2)) = 0
(-16 + -4x + 12x + 3x2 + (8x2 + 2x3)) = 0

Combine like terms: -4x + 12x = 8x
(-16 + 8x + 3x2 + 8x2 + 2x3) = 0

Combine like terms: 3x2 + 8x2 = 11x2
(-16 + 8x + 11x2 + 2x3) = 0

Solving
-16 + 8x + 11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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